49s^2-14=0

Solution for 49s^2-14=0 equation:

49s^2-14=0

a = 49; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·49·(-14)
Δ = 2744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2744}=\sqrt{196*14}=\sqrt{196}*\sqrt{14}=14\sqrt{14}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{14}}{2*49}=\frac{0-14\sqrt{14}}{98}
=-\frac{14\sqrt{14}}{98}
=-\frac{\sqrt{14}}{7}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{14}}{2*49}=\frac{0+14\sqrt{14}}{98}
=\frac{14\sqrt{14}}{98}
=\frac{\sqrt{14}}{7}
$